@Jisoo2506 Can you post answers for this Question... pls dont Spam..
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ok here ......
- Given,
- The ratio of two consecutive angles of a parallelogram = 1 : 3
- Let x and 3x be the two consecutive angles.
- We know that the sum of interior angles on the same side of the transversal is 180°.
- Therefore, x + 3x = 180°
- 4x = 180°
- x = 180°/4
- x = 45°
- ⇒ 3x = 3(45°) = 135°
- Thus, the measure of two consecutive angles is 45° and 135°.
- As we know, the opposite angles of a parallelogram are equal.
- Hence, the measure of all the four angles is 45°, 135°, 45°, and 135°.
2. We know that the opposite angles of a parallelogram are equal.
- ∠A = ∠C = 80°
And
- ∠OCB = (1/2) × ∠C
- = (1/2) × 80°
- = 40°
- ∠B = 180° – ∠A (the sum of interior angles on the same side of the transversal is 180)
- = 180° – 80°
- = 100°
Also,
- ∠CBO = (1/2) × ∠B
= (1/2) × 100°
= 50°
- By the angle sum property of triangle BCO,
∠BOC + ∠OBC + ∠CBO = 180°
∠BOC = 180° – (∠OBC + CBO)
= 180° – (40° + 50°)
= 180° – 90°
= 90°
Hence, the measure of all the three angles of a triangle BCO is 40°, 50° and 90°.
see the image of 2nd pic in attachment .........
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