Question

@Jisoo2506 Can you post answers for this Question... pls dont Spam.. ​

Answer 1

Answer:

ok here ......

1. Given,
2. The ratio of two consecutive angles of a parallelogram = 1 : 3
3. Let x and 3x be the two consecutive angles.
4. We know that the sum of interior angles on the same side of the transversal is 180°.
5. Therefore, x + 3x = 180°
6. 4x = 180°
7. x = 180°/4
8. x = 45°
9. ⇒ 3x = 3(45°) = 135°
10. Thus, the measure of two consecutive angles is 45° and 135°.
11. As we know, the opposite angles of a parallelogram are equal.
12. Hence, the measure of all the four angles is 45°, 135°, 45°, and 135°.

2. We know that the opposite angles of a parallelogram are equal.

• ∠A = ∠C = 80°

And

• ∠OCB = (1/2) × ∠C
• = (1/2) × 80°
• = 40°
• ∠B = 180° – ∠A (the sum of interior angles on the same side of the transversal is 180)
• = 180° – 80°
• = 100°

Also,

• ∠CBO = (1/2) × ∠B

= (1/2) × 100°

= 50°

• By the angle sum property of triangle BCO,

∠BOC + ∠OBC + ∠CBO = 180°

∠BOC = 180° – (∠OBC + CBO)

= 180° – (40° + 50°)

= 180° – 90°

= 90°

Hence, the measure of all the three angles of a triangle BCO is 40°, 50° and 90°.

see the image of 2nd pic in attachment .........

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