∆ATM~∆AHE. IN ∆AMT,AM=6.3 CM,ANGLE TAM=50°,AND AT=5.6CM AM/ AH=7/5? construct∆AHE
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constructed ∆AHE
Step-by-step explanation:
∆AMT ~∆AHE
=> AM/AH = AT/AE = MT/HE
∠TAM = ∠EAH
AM/AH = 7/5
AM =6.3 cm
=> 6.3/AH = 7/5
=> AH = 4.5 cm
AT/AE = 7/5
AT = 5.6 cm
=> 5.6/AE = 7/5
=> AE = 4 cm
∠TAM=50°
=> ∠EAH = 50°
Step 1 : Draw a line segment AH = 4.5 cm using ruler
Step 2 : Draw an angle of 50° at A on AH using protector
Step 3 : Take a length of 4 cm from A on angle drawn in step 2 and label other end as E
Step 4 : join EH
∆AHE is constructed
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