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What is the work to be done to increase the velocity of a car from 30km/h to 60km/h if the mass of car is 1500kg?
Answers
Answered by
2
Answer:
Work = Change in kinetic energy
= 0.5 m (v² - u²)
= 0.5 × 1500 kg × [(60 × 5/18 m/s)² - (30 × 5/18 m/s)²]
= 156250 joules
= 156.25 kJ
Work done is 156.25 kJ
Answered by
25
Answer:
- The work done = 156250 J
Explanation:
Given,
- Mass of car, m = 1500kg
- Initial velocity of car, u = 30km/h
- Final velocity of car, v = 60km/h
To Find,
- The work done.
Solution,
u = 30km/h
- u = 25/3 m/s
v = 60km/h
- v = 50/3 m/s
The Initial kinetic energy = ½ m u²
- → E(ki) = ½ × 1500kg × (25/3 m/s)²
- → E(ki) = ½ × 625000/3 kg m²/s²
- → E(ki) = 156250/3 kg m²/s²
- → E(ki) = 156250/3 J
The Final kinetic energy = ½ m v²
- → E(kj) = ½ × 1500kg × (50/3 m/s)²
- → E(kj) = ½ × 1250000/3 kg m²/s²
- → E(kj) = 625000/3 kg m²/s²
- → E(kj) = 625000/3 J
The work done = Change in kinetic energy
- → The work done =E(kj) - E(ki)
- → The work done = 156250 J
Required Answer,
- The work done = 156250 J
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