Question

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The length of rectangle is 10 more than its breadth if the perimeter of rectangle is 400 m find its Length , breadth and area?????????

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Answer 1

hey mate here ure answer

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area of rectangle = l×b

105×95=9975

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Answer 2

Given,

• The Length of Rectangle is 10 more than its breadth .
• Perimeter of Rectangle = 400 m

To Find,

• Length of Rectangle = ?
• Breadth of Rectangle = ?
• Area of Rectangle = ?

Solution,

⇒Suppose the Breadth of Rectangle be b

So,The Length of Rectangle = Breadth + 10

$\mapsto \underline{\sf{\pink{According \ to \ the \ Question :}}}$

$\implies \boxed{\sf{Perimeter \ of \ Rectangle = 2(Length + Breadth)}}$

$\implies \sf{Perimeter \ of \ Rectangle = 2(b + 10) + b}$

$\implies \sf{2(2b + 10) = 400}$

$\implies \sf{4b + 20 = 400}$

$\implies \sf{4b = 400 - 20}$

$\implies \sf{4b = 380}$

$\implies \sf{b = \dfrac{380}{4}}$

$\implies \boxed{\sf{b = 95m}}$

Therefore,

• Length of Rectangle =  $\sf{b + 10 = 95 + 10 = 95}$

$\mapsto \boxed{\sf{\red{Now, \ Find \ Area \ of \ Rectangle :}}}$

$\implies \sf{Area \ of \ Rectangle = Length \times Breadth}$

$\implies \sf{Area \ of \ Rectangle = 105 \times 95}$

$\implies \underline{\boxed{\sf{\purple{Area \ of \ Rectangle = 9975m^{2}}}}}$

$\rule{200}2$