Math, asked by mcadamselena12, 21 days ago

Atn elevator descends into a mine shaft at the rate of 5m pet minute. What will be it's position after 1hr?
pls answer it fast

Answers

Answered by mandanageswararao9

2

Answer:

after 1hour=5×60=300. It's position will be=15-300=-285=285m below the ground.

Answered by sunilkumar1983

2

Answer:

After 1 Hour - 5x60-300. It's position will be=15-300=-285-285m below the ground.

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