Question

Atom of X form ccp lattice and Atom of Y occypies all the Tetrahedral voids . If all the atoms from one face diagonal is removed then . what is the resultant stoicheometry of the compound

Answer 1

Atom of X forms ccp lattice, so the contribution of X is,

• $\tt{Z_X=4}$

Atom of Y occupies all the tetrahedral voids, so its contribution is,

• $\tt{Z_Y=8}$

But all the atoms from one face diagonal is removed.

In a face diagonal there are 3 X atoms; 2 at corners and 1 at face center.

So the contribution of X will be,

$\tt{\longrightarrow Z_X'=4-\dfrac{1}{8}\times2-\dfrac{1}{2}\times1}$

$\tt{\longrightarrow Z_X'=\dfrac{13}{4}}$

Then the formula of the compound will be $\tt{X_{\frac{13}{4}}Y_8\leadsto\underline{\underline{X_{13}Y_{32}}}}$

Answer 2

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Atom of X forms ccp lattice, so the contribution of X is,

$\tt{Z_X=4}$

Atom of Y occupies all the tetrahedral voids, so its contribution is,

$\tt{Z_Y=8}$

But all the atoms from one face diagonal is removed.

In a face diagonal there are 3 X atoms; 2 at corners and 1 at face center.

So the contribution of X will be,

$\tt{\longrightarrow Z_X'=4-\dfrac{1}{8}\times2-\dfrac{1}{2}\times1}$

$\tt{\longrightarrow Z_X'=\dfrac{13}{4}}$

Then the formula of the compound will be $\tt{X_{\frac{13}{4}}Y_8\leadsto\underline{\underline{X_{13}Y_{32}}}}$