Atom Z is found to be 12 times as heavy as an atom X. If one wished to prepare a compound with a formula Z3X5, how many grams of Z would be required to combine with 1g of X?
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Atom Z is found to be 12 times as heavy as an atom X. one wished to prepare a compound with a formula Z₃X₅.
We have to find the number of grams of Z would be required to combine with 1g of X.
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Atom Z is found to be 12 times as heavy as an atom X.
∴ atomic mass of Z = 12 × atomic mass of X ...(1)
chemical formula of compound Z₃X₅ , it indicates that 3 moles of Z atoms combine with 5 moles of X atoms.
i.e., no of moles of Z/no of moles of X = 3/5
∴ 5 × no of moles of Z = 3 × no of moles of X.
⇒ 5 × mass of Z/atomic mass of Z = 3 × mass of X/atomic mass of X
here mass of X = 1g and from equation (1) we get,
⇒ 5 × mass of Z/(12 × atomic mass of X) = 3 × 1g/atomic mass of X
⇒ mass of Z = 36/5 = 7.2 g
Therefore 7.2g of Z would be required to combine with 1g of X.
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