Question

Atom Z is found to be 12 times as heavy as an atom X. If one wished to prepare a compound with a formula Z3X5, how many grams of Z would be required to combine with 1g of X?

Answer 1

Answer:

$\frac{3}{5} times \: of \: moles \: of \: x \: taken$

Explanation:

$if \: x \: is \: 1grms \: then \: z \: is \: 12grms \: to \: form \: z3x5 \: we \: need \: \frac{3}{5} times \: moles \: of \: x \: taken$

Answer 2

Atom Z is found to be 12 times as heavy as an atom X. one wished to prepare a compound with a formula Z₃X₅.

We have to find the number of grams of Z would be required to combine with 1g of X.

A/C to question,

  Atom Z is found to be 12 times as heavy as an atom X.

∴ atomic mass of Z = 12 × atomic mass of X   ...(1)

chemical formula of compound Z₃X₅ , it indicates that 3 moles of Z atoms combine with 5 moles of X atoms.

i.e., no of moles of Z/no of moles of X = 3/5

∴ 5 × no of moles of Z = 3 × no of moles of X.

⇒ 5 × mass of Z/atomic mass of Z = 3 × mass of X/atomic mass of X

here mass of X = 1g and from equation (1) we get,

⇒ 5 × mass of Z/(12 × atomic mass of X) = 3 × 1g/atomic mass of X

⇒ mass of Z = 36/5 = 7.2 g

Therefore 7.2g of Z would be required to combine with 1g of X.