Question

Atomic mass of Al is 27 and atomic number is 13 calculate the no of electrons protons and neutron in ion formed. what will be it's valency?

Answer 1

ec = 2,8,3

no of electrons = protons =3 (valence electrons)

neutrons = atomic no- atomic mass= 14

valency = 3

Answer 2

Explanation:

Heya!!

Here is your answer!!

Atomic number of Al=13.

Mass number of Al =27.

Al3+=Removing 3 electrons from Al.

Number of protons of Al3+= 13.

Number of electrons of Al3+=13-3=10.

Number of Neutrons of Al3+=13.

Electronic configuration of Al+3:

2,8.

$1 {s}^{2} 2 {s}^{2} 2 {p}^{6}1s </p><p>2$

$2s </p><p>2</p><p> 2p </p><p>6$

Valency of Al is 3 as it has 3 electrons in its outermost shell.

Hope it helps u!!