Atomic mass of iron is 56 its oxide contain 7 of iron callculate it
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Empirical formula of a compound may be defined as the formula which gives the simplest whole number ratio of the atoms of various elements present in one molecule of the compound. Form the available data Percentage of iron = 69.9 Percentage of oxygen= 30.1 Total percentage of iron & oxygen= 69.9+30.1= 100% Step 1 calculation of simplest whole number ratios of the elementsElementPercentageAtomic massAtomic ratioSimplest ratioSimplest whole no ratioFe69.955.8469.9/55.84=1.251.25= 12O30.11630.1/16 = 1.881.88=1.53Step 2 writing the empirical formula of the compound The empirical formula of the compound = Fe2 O3
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