Question

Atomic mass of Si is 28 g. How many silicon atoms are there in 1.00 g of silicon?
(i) 2.14 X 1022 atoms (ii) 1.75 X 1025 atoms
(iii) 1 atom
(iv) 0.0356 atoms​

Answer 1

Given: Atomic mass of Si is 28 g.

To find: We have to find the number of atoms of silicon present in 1g silicon.

Solution:

Si is an element of the carbon family.

The atomic mass of the Si atom is 28 grams.

28g of silicon is equal to 1 mole.

28 gram of silicon contains $6.023×10^{23}$ number of atoms.

Thus 1 gram of silicon contains $6.023×10^{23}/28=2.15×10^{22}$ number of atoms.

Thus 1 gram of silicon contains $2.15×10^{22}$ number of atoms.

Hence the correct option is (i).

Answer 2

Answer:

option (1)

Explanation:

28 g of silicon = 6.022*10^23 atoms

1 g of silicon = 6.022*10^23 / 28

ie; 2.14 * 10^22

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