Chemistry, asked by rahulnayak33, 2 days ago

Atomic number & mass number of an elements 29 & 64. How many protons & neutrons are present in if? write the Electronic configuration of the Element

Answers

Answered by steshickamilo
29

Answer:

protons = 29

neutrons = 35

electronic configuration = 2,8,8,8,3

Answered by Anonymous
32

Explanation:

Atomic number & mass number of an elements 29 & 64. No of protons = 29 = no of electrons = atomic number.

No of neutrons = mass no - atomic number= 64 - 29 = 35 are present

2n² is the formula in which the electrons are arranged in cells. n=1,2,3,...

K cell 2 electrons, L cell 8 electrons, M cell 18, and hence N cell can have rest 1 electron

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