Atomic number & mass number of an elements 29 & 64. How many protons & neutrons are present in if? write the Electronic configuration of the Element
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Answered by
29
Answer:
protons = 29
neutrons = 35
electronic configuration = 2,8,8,8,3
Answered by
32
Explanation:
Atomic number & mass number of an elements 29 & 64. No of protons = 29 = no of electrons = atomic number.
No of neutrons = mass no - atomic number= 64 - 29 = 35 are present
2n² is the formula in which the electrons are arranged in cells. n=1,2,3,...
K cell 2 electrons, L cell 8 electrons, M cell 18, and hence N cell can have rest 1 electron
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