Question

Atomic number of A,B and C are 12,10 and 9 respectively.  So A,B and C will be: (0.5 Points)
Metal – A ; Non-metal –B ; Inert gas – C
Metal – C ; Non-metal –B ; Inert gas – A
Metal – C ; Non-metal –A ; Inert gas – B
Metal – A ; Non-metal –C ; Inert gas – B​

Answer 1

Answer:

Correct option is C)

C is an alkali metal with atomic number a+2. Hence, B with the atomic number a+1 must be an inert gas. Because on moving towards right of the periodic table from alkali metals family i.e. from s-block elements we reach at inert gas family series that is at 18

th

group.

Thus, the element A with the atomic number a must be an element belonging to the halogen group, because it comes before the inert gas group.

Since halogens are non-metal and with alkali metals they will form ionic bonding.

The correct option is C.

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Answer 2

Answer:

alkali metal with atomic number a+2. Hence, B with the atomic number a+1 must be an inert gas. Because on moving towards right of the periodic table from alkali metals family i.e. from s-block elements we reach at inert gas family series that is at 18th group.  

Thus, the element A with the atomic number a must be an element belonging to the halogen group, because it comes before the inert gas group.

Since halogens are non-metal and with alkali metals they will form ionic bonding.

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