Question

Atomic number of an atom Z=17, Mass Number A=35.
a) Find the number of protons, electrons and neutrons in the
atom.
b) Write the electronic configuration of the atom. - 2,87​

Answer 1

Answer:

The atom is chlorine

Explanation:

The no. Of protons and electons is 17

The number of neutrons is 28

Electronic configuration is

K shell-2

L shell-8

M shell-7

Answer 2

• no. of electrons=17 (no. of electrons are same as the atomic number)
• no. of protons=17 (no. of protons are equal no. of electrons)
• no. of neutrons=18 (no. of neutrons=mass no. -no. of protons)

The electronic configuration of the given element is given by 2,8,7 or

$1 {s}^{2}2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{5}$

or

$[Ne] 3{s}^{2} 3 {p}^{5}$

The given element was Chlorine

Hope this answer would be helpful mark as brainliest