Atomic number of an element is 13. The number of
cations in 0.102 g of its oxide is will be
0 1.2044 X 1024
1.2041 x 1023
0 1.2044 x 1021
6.022 x 1023
Answers
Answered by
7
Answer:
Aluminum
6.022×1023
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Answered by
0
Answer:
opt 3
Explanation:
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