Atomic number of chlorine is 17 and mass number is 19. Calculate the number of electrons, protons and neutrons in the neutral form and its ion. Represent the ion and give its electric configuration.
Answers
Answer:
The atomic number of Chlorine is 17 and mass number is 35.
(a) What would be the electronic configuration of negatively charged chlorine ion, Cl-?
(b) What would be the atomic number and mass number of Cl-?
(c) Define valency and calculate the valency of Cl-.
OR
(a) Consider the atom begin mathsize 12px style straight B presubscript 5 presuperscript 10 end style.
(i) What does the figures 5 and 10 indicate?
(ii) How many number of electrons does this element contain?
(iii) The relative atomic mass of Boron is 10.8 u. Calculate the percentage of its isotopes begin mathsize 12px style straight B presubscript 5 presuperscript 10 end style and begin mathsize 12px style straight B presubscript 5 presuperscript 11 end style, occurring in nature.
Explanation:
(a) Chlorine atom (Cl) has atomic number 17. It contains 17 protons and 17 electrons.
Chlorine ion (Cl-) is formed when Cl gains one electron.
So, Cl- has 18 electrons and 17 protons.
Therefore, the electronic configuration of Cl- = 2, 8, 8.
(b) Atomic number of Cl- = Number of protons = 17
Mass number of Cl- will be the same as Cl i.e. 35.
(c) Valency is defined as the combining capacity of an atom.
For a non-metallic element, it is equal to eight minus the number of electrons present in outermost shell.
Here, Cl- has 8 electrons in the outermost shell, therefore valency of Cl- = 8 - 8 = 0
(a) (i) 5 is the atomic number.
10 is the atomic mass number.
(ii) Number of neutrons = Mass number - Atomic number
= 10 - 5
= 5
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