Question

Atomic number of element 'A' & 'B' are 11 & 9 respectively. The type of chemical bond in 'AB' compound is a. Covalent b. Co-ordinate covalent c Electrovalent d. Hydrogen bond​

Answer 1

Answer:

Atomic number of A = 11 => A is Na (Sodium)

Atomic number of B = 9 => B is F (Fluorine)

=> AB = NaF = ionic(electrovalent) bond

Answer 2

Answer:

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Explanation:

For A, electronic configuration is 2,8,1 therefore it's valancy is 1 .

For B, EC is 2,7 Hence its valency is also 1.

But charge on A is +1 and that on B is -1

Hence they will form ionic bond i. e. Electrovalent bond.