Question

Atomic number of metal "A" is 11, while atomic number of metal "B" is 20.
Which of them will be more reactive? Write the chemical reaction of dilute
HCI with metal "A".
inne​

Answer 1

Required Answer:-

Atomic number of ‘A’ is 11.

Electronic configuration of ‘A’ will be 2,8,1.

Hence:

• The element is Sodium (Na) as its Atomic number is 11.

Also,

Atomic number of ‘B’ is 20.

Electronic configuration of ‘B’ will be 2,8,8,2.

Hence:

• The element is Calcium (Ca) as its Atomic number is 20.

Therefore:

Metal ‘A’ is more reactive than metal ‘B’.

Reaction:

$\large{\underline{\boxed{\sf 2Na + 2HCl \longrightarrow 2NaCl + H_2}}}$

Where,

• Na → Sodium
• HCl → Hydrochloric acid
• NaCl → Sodium chloride
• H2 → Hydrogen