atomic radii of Ti and In are almost equal . explain
Answers
yes for your confirmnation
Given:
The atomic radii of Ti and In are almost equal
To Find:
Solution:
d-orbitals do not screen nuclear charge as effectively as those in s and p orbitals. This is called penetration. The shapes of d-orbitals prevent them from allowing electrons to penetrate very closely to the nucleus, compared with electrons in s or p-orbitals. In gallium, you have 10 electrons in the filled 3d-subshell with a poor screening effect than the electrons in the s and p orbitals. Therefore, the effective nuclear charge in gallium is slightly higher than that of aluminum, so the increase in the radius is quite a bit smaller than expected based on the difference between boron and aluminum, or gallium and indium.
- The atomic radius of Boron is 82 pm.
- The atomic radius of Aluminium is 118 pm.
- The atomic radius of Gailum is 126 pm.
- The atomic radius of Indium 144 pm.
This effect is generally known as the d-block contraction. The same thing happens when we go from indium to thallium but there is an f-subshell also. Electrons in f-orbitals are even worse at screening nuclear charge than those in d-orbitals, therefore again, the effective nuclear charge in thallium is a bit larger than it is in indium, so the increase in atomic radii is a bit smaller (from 144 to 148 pm). This effect (of the filled f-subshell) is generally known as the lanthanide contraction.