Chemistry, asked by RjRahulSankhyan, 1 month ago

atomic radii of Ti and In are almost equal . explain ​


amishadhiman2000: yeh to question mein bhi h

Answers

Answered by abhaygautam6
1

yes for your confirmnation


amishadhiman2000: yeh toh question mein bhi h
Answered by rishikeshm1912
0

Given:

The atomic radii of Ti and In are almost equal

To Find:

Solution:

d-orbitals do not screen nuclear charge as effectively as those in s and p orbitals. This is called penetration. The shapes of d-orbitals prevent them from allowing electrons to penetrate very closely to the nucleus, compared with electrons in s or p-orbitals. In gallium, you have 10 electrons in the filled 3d-subshell with a poor screening effect than the electrons in the s and p orbitals. Therefore, the effective nuclear charge in gallium is slightly higher than that of aluminum, so the increase in the radius is quite a bit smaller than expected based on the difference between boron and aluminum, or gallium and indium.

  1. The atomic radius of Boron is 82 pm.
  2. The atomic radius of Aluminium is 118 pm.
  3. The atomic radius of Gailum is 126 pm.
  4. The atomic radius of Indium 144 pm.

This effect is generally known as the d-block contraction. The same thing happens when we go from indium to thallium but there is an f-subshell also. Electrons in f-orbitals are even worse at screening nuclear charge than those in d-orbitals, therefore again, the effective nuclear charge in thallium is a bit larger than it is in indium, so the increase in atomic radii is a bit smaller (from 144 to 148 pm). This effect (of the filled f-subshell) is generally known as the lanthanide contraction.

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