Question

Atomic radius of f, li and ne is in order
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Answer 1

Answer:

Correct option is

D

F<N<Be<Li

In a period as outer most shell remains same and the difference comes only with number of protons that is nuclear charge. As we move from left to right nuclear charge increases this increases the affect of nuclear charge on the outer most shell making radius decrease. Hence, fluorine is at the end in the 2nd period and lithium comes first in this period after lithium, beryllium and then nitrogen.

F<N<Be<Li.

Answer 2

F <Li<Ne

this is a increasing order of atomic radius , with flourine having smallest atomic radius and sodium being the largest atomic radius .

as the atomic number increases across the periodic table , number of protons also increases . Because of higher number of protons , it attracts the election of its atom by greater force , thus the smaller atomic radius . ( each element across the period have same shell/orbital )

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