ATOMIC STRUCTURE
61. The de-Broglie wavelength of an electron accelerated by an electric potential of V volts is given
by:
1.23
1.23
1.23
(a) lemda =1.23/√m
b lemda=1.23/√h
c lemda =1.23/√v nm
Answers
Answered by
1
the answer is c)
Remember it, it is a short trick to do such questions of electron and potential quickly
Answered by
0
Answer:
The answer is (c)
Explanation:
It help you to solve question of electron
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