Question

Atoms and Molecules​​​​​MM 35

Q1​In an experiment , 5.7 g of copper oxide was obtained from 1.9 g of copper. In another experiment, 4.5 g of copper oxide gave, on reduction, 1.5 g of copper. Show with the help of calculations that these figures verify the law of constant proportions. ​​​​​

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Answer 1

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In the first experiment:-

Weight of copper oxide, (CuO)=1.288g

Weight of copper =1.03g

Weight of oxygen = Wt. of copper oxide − Wt. of copper =1.288−1.03=0.258g

∴ Wt. of copper/Wt. of oxygen

= 1.03/0.258

≈ 4/1

In the second expriment:-

Weight of copper oxide (CuO)=3.672g

Weight of copper =2.938g

Weight of oxygen = Wt. of copper oxide − Wt. of copper =3.672−2.938=0.734g

∴ Wt. of copper/Wt. of oxygen

= 2.938/0.734

≈ 4/1

The proportion of elements of copper and oxygen in the reactions is same.

Hence law of constant proportion is proved.

Answer 2

Answer:

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