Atoms gain the same electron configuration as noble gases by
A.losing protons.
B.losing electrons.
C.gaining electrons.
D.losing or gaining electrons.
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option d) by losing or gaining electrons
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Heya !
Option (D) is your answer - “losing or gaining electrons”
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Why is option (D) the answer ?
Atoms of elements that need to attain stability will obviously lack an octet on their outermost shell. They might have 1 electron to 7 electrons on their valence shell. If they have electrons from the range 1-4, it is easier for them to lose these electrons so that the inner shell that is already filled becomes a completed valence shell. On the other hand, if they have electrons from the range 5-7, it is easier to for them to gain the remaining electrons to complete the octet p. For example, Chlorine has 7 electrons on its valence shell. It needs only one more to complete the octet. Hence instead of losing all 7, it gains 1. Similarly, sodium has 1 electron in its valence shell. It can lose that one electron and expose the inner shell (L shell) as its valence shell as it already has an octet.
So in conclusion, depending on the number of valence electrons, the atoms can either gain or lose electrons to complete their octet (or doublet in case of Helium)
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Hope this helps ya✌️
Option (D) is your answer - “losing or gaining electrons”
▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️
Why is option (D) the answer ?
Atoms of elements that need to attain stability will obviously lack an octet on their outermost shell. They might have 1 electron to 7 electrons on their valence shell. If they have electrons from the range 1-4, it is easier for them to lose these electrons so that the inner shell that is already filled becomes a completed valence shell. On the other hand, if they have electrons from the range 5-7, it is easier to for them to gain the remaining electrons to complete the octet p. For example, Chlorine has 7 electrons on its valence shell. It needs only one more to complete the octet. Hence instead of losing all 7, it gains 1. Similarly, sodium has 1 electron in its valence shell. It can lose that one electron and expose the inner shell (L shell) as its valence shell as it already has an octet.
So in conclusion, depending on the number of valence electrons, the atoms can either gain or lose electrons to complete their octet (or doublet in case of Helium)
▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️▶️
Hope this helps ya✌️
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