Question

atoms of a element X from hcp lattice and those element Y from occupy two third of the tetrahedral voids . Determine the formula of the compound formed by the elements X andY?​

Answer 1

There are totla 6 atoms in hcp lattice... so x = 6

Now , tetrahedral voids will be = 2N = 2*6 = 12 But given , Y = 2/3 * 2N = 2/3 * 12 = 8

hence , Y = 8 & X =6

so Formula of the compound = X6Y8 = X3Y4

hope it helps..

Answer 2

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\purple{R}}}}$

• ❤.. The number of tetralhedral voids formed is equal to twice the number of atoms of element B and only 2/3rd of these are occupied by the atoms of element A.
• ❤..Hence the ratio of the number of atoms of A and B is ${2×(2/3):1 or 4:3}$ and the formula of the compound is ${A4B3}$.