Atoms of an element A form hcp lattice and of element B occupy 2/3 octahedral voids. What is the formula
of the compound formed by the elements A and B.
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Since only 2/3 of tetrahedral voids are occupied by the atoms of the element A. ∴ Number of atoms of A in hcp lattice=2n×2/3=4n/3. Ratio of A:B=4n/3:n=4n:3n=4:3. The formula of compound AB = A4B3
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