Question

Atoms of element B forms hcp lattice and those of element A occupy two third of the tetrahedral voids. What is the formula of the compound?

Answer 1

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Answer 2

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• ❤.. The number of tetralhedral voids formed is equal to twice the number of atoms of element B and only 2/3rd of these are occupied by the atoms of element A.
• ❤..Hence the ratio of the number of atoms of A and B is ${2×(2/3):1 or 4:3}$ and the formula of the compound is ${A4B3}$.