Atoms of elements A and B form Molecules Ax By and
Cyrstallises in hcp lattice. The element A occupy
1/2 of the tetrahedral voids. calculate x and y
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Answer:
Given that, atoms of B forms hcp lattice. So, the atoms at corners are shared by 6 unit cells. So, its contribution is
6
1
; Face centered atoms contribute
2
1
and middle layer atoms contribute 1 each.
So, effective number of atoms in unit cell =
6
1
×12+
2
1
×2+1×3
=2+1+3=6
Number of tetrahedral voids =2× Number of atoms forming the lattice.
=2×6=12
So, number of atoms of A=
3
2
×12=8
Number of atoms of B=6
So, A:B⇒A:B
8:6 4:3
So, formula is A
4
B
3
hope it helps
thank u
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