Question

ATrain starting from rest attains a Velocity of 72 kilometers per hour in 5 minutes assuming that the acceleration is uniform find the acceleration and the distance travel by the train from attending this velocity​

Answer 1

the acceleration is 4 m/s and distance travelled is 50 km....

sorry in the img. I wrote 50 m(by mistakenly )

Answer 2

Answer:

Question :

A train starting from rest attains a velocity of 72 kilometre per hour in 5 minutes assuming that the acceleration is uniform, find the acceleration and the distance travelled by the train for attending the velocity ?

Answer :

Given,

initial velocity (u) = 0 ;

final velocity (v) = 72 km/hr ;

$72 \times \frac{5}{18} \\ 4 \times 5$

20 m/s

Time (t) = 5min = 300 s

Now,

1. Acceleration =

$a = \frac{v - u}{t}$

$a = \frac{20 - 0}{300} \\ \frac{1}{15}m \: s {}^{ - 1}$

2. Distance =

From equation

$2 \: a \: s = v {}^{2} - u {}^{2} \\ v {}^{2} - 0$

Thus,

$s = \frac{v {}^{2} }{2a} \\ \frac{20}{2 \times 1 \div 15}$

3000 m

Change m in km

3 km

The acceleration of the train is 1/15 metre per second and the distance travelled in 3 km