Question

Atrain starts from rest, and it start to accelerate. it reaches a velocity of 2m/s after 1 secand, what is the acceleration?

Answer 1

Answer:

0.2 m/s²

Explanation:

Given :

• Initial velocity of the train = u = 0 m/s

• Final velocity of the train = v = 2 m/s

• Time taken = t = 10 seconds

To find :

• Acceleration of the train

Acceleration = (v-u) /t

Acceleration = (2-0)/10

Acceleration = 2/10

Acceleration = 1/5

Acceleration = 0.2 m/s²

The acceleration of the train is equal to 0.2 m/s²

Answer 2

Given :

• Initial velocity (u) = 0 m/s
• Final velocity (v) = 2 m/s
• Time interval (t) = 1 second

To Find :

• Acceleration

Solution :

We're given that a train starts from rest and starts acceleration it means that the final velocity (u) is 0 m/s, and attains a velocity of 2 m/s it means final velocity (v) is 2 m/s. Time interval is given as 1 second.

Use 1st equation of motion :

⇒v = u + at

⇒v - u = at

⇒2 - 0 = a * 1

⇒a = 2

So, acceleration of the train is 2 m/s².

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• Acceleration is defined as rate of change of velocity.

• It is denoted by “a”.

• SI unit of acceleration is m/s²

• Instantaneous acceleration is given by $\sf{a \: = \: \dfrac{dv}{dt}}$ .