Question

Atriangle ABC is drawn to circumscibe
a circle and AD=6 cm, DB=4 cm and
CF=3 cm then find perimeter of a triangle ABC.

Answer 1

ANSWER

26

TANGENTS ARE EQUAL

THEREFORE

$2(6 + 4 + 3)$

$2 \times 13$

$26$

Answer 2

As we know that

Tangents Drawn from external point to a circle are equal.

Therefore, AD=AF

BD=BE

and CE=CF

Given that: AD= 6cm

BD= 4cm

CF=3cm

So, AF= 6cm

BE= 4cm

CE= 3cm

Then,

AB= AD+BD

     =6cm+4cm

     = 10cm

BC=BE+CE

    =4cm+3cm

    = 7cm

AC=AF+CF

    =6cm+3cm

    = 9cm

Hence, perimeter of triangle ABC= AB+BC+AC=10+7+9=26cm

That's your answer

Hope this clarifies your doubt..