att If x + y = 5 and xy = 6. Find the value of x² + y 2 and x-y
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Answer:
x^+y^2 = 13 , x-y= 1
Step-by-step explanation:
x+y=5
xy=6
(x+y)^2 = x^2+y^2 +2xy
5^2= x^2 + y^2 + 2×6
25=x^2+y^2+12
25-12 = x^2 + y^2
x^2 +y^2 = 13
(x-y)^2=x^2 + y^2 -2xy
(x-y)^2 = 13- 2×6
(x-y)^2= 13-12
(x-y)^2 =1
x-y = 1
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