Question

att If x + y = 5 and xy = 6. Find the value of x² + y 2 and x-y

please answer it
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Answer 1

Answer:

x^+y^2 = 13 , x-y= 1

Step-by-step explanation:

x+y=5

xy=6

(x+y)^2 = x^2+y^2 +2xy

5^2= x^2 + y^2 + 2×6

25=x^2+y^2+12

25-12 = x^2 + y^2

x^2 +y^2 = 13

(x-y)^2=x^2 + y^2 -2xy

(x-y)^2 = 13- 2×6

(x-y)^2= 13-12

(x-y)^2 =1

x-y = 1

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