Question

Attempt 1) The no of carbon atoms present in 112ml of ethane gas at STP ​

Answer 1

what is this a question I don't know the answer

Answer 2

Answer:

6.023*10^21

Explanation:

22400ml of C2H6 at STP =6.023*10^23

molecules of C2H6 =2*6.023*10^23 atoms of carbon

112 ml of C2H6 at STP = 2*6.023*10^23/22400*112 atoms of carbon=6.023*10^21