Attention!!
A motorcar of mass 1200kg. Is moving along a straight line with a uniform velocity of 90 km/h. Its velocity is slowed down to 18 km/h in 4s by an unbalanced force. Calculate the acceleration and change in momentum. Also calculate the magnitude of the force required.
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Answer:-
》Mass of motor car , m = 1200 kg.
Initial velocity of car, u= 90 km/h .
(90 × 5/18) = 25m/s
》Final velocity of car , v = 18 km/h.
(18 × 5/18) = 5m/s.
》Time , t = 4s.
》 Acceleration , a = v-u /t = 5-25/4
- -20/4 = -5 m/s^2.
》 Momentum change = mv = 1200 × (5-25)
- =1200 × 20 = -2400 kgm/s.
》Magnitude of force, f= ma
- = 1200 × -5 = -6000N.
●Acceleration , momentum change and the force are opposing the motion of motor car as indicated by the negative side.
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