Physics, asked by Anonymous, 10 months ago

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A motorcar of mass 1200kg. Is moving along a straight line with a uniform velocity of 90 km/h. Its velocity is slowed down to 18 km/h in 4s by an unbalanced force. Calculate the acceleration and change in momentum. Also calculate the magnitude of the force required.​

Answers

Answered by surajrhhh
9

Explanation:

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Answered by Anonymous
27

Answer:-

Mass of motor car , m = 1200 kg.

Initial velocity of car, u= 90 km/h .

(90 × 5/18) = 25m/s

Final velocity of car , v = 18 km/h.

(18 × 5/18) = 5m/s.

Time , t = 4s.

Acceleration , a = v-u /t = 5-25/4

  • -20/4 = -5 m/s^2.

》 Momentum change = mv = 1200 × (5-25)

  • =1200 × 20 = -2400 kgm/s.

Magnitude of force, f= ma

  • = 1200 × -5 = -6000N.

Acceleration , momentum change and the force are opposing the motion of motor car as indicated by the negative side.

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