Question

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The sum of the ratio of nth term〽 of A.P is (7n+1):(4n+27).

☦Then find the ratio on their 9th term​

Answer 1

Answer:

here is ur answer....

Step-by-step explanation:

Given the ratio of sum of n terms of two APs =(7n+1):(4n+27).We can consider the 9th term as the mth term .

Let's consider the ratio these two APs mth term as am :a'm -(2).

Recall the nth term of AP formula , an =a +(n-1)d .

Hence equation (2) becomes , am :a'm =a +(m-1)d :a'm [2a+2(m-1)d]:[2a'+{(2m -1) - 1)d'}

= (2a+{(2m-1)-1}d] : [ 2a' +{(2m -1)d']

= S2m - 1 : S'2m-1

= [7(2m -1) +1] : [4(2m-1) +27]

= [14m -7 +1] : [8m -4+27]

= [14m -6] : [ 8m +23]

Thus the ratio of mth terms of two APs is [14m-6] : [8m+23].

Now substitute the value of m as 9 .

So the answer becomes 120 /95.

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