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Answer :- (A) 4R/3π
Explanation :- centre of mass of uniform quarter disc .
Mass per unit area of disc = M/πR²/4 = 4M/πr²
Area of the assumed element = 1/2πrdr
dm = (1/2 πrdr )4M/πR² = 2Mr/R²dr
Xcm = 1/M [xdm ] limit 0 to R , putting , we get
4R/3π
similarly , ycm = 4R/3π
Hence option (A) is correct option .
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