Question

ATTENTION !!!!!!!!
Please help me

Answer 1

$\mathfrak{\huge{\orange{\underline{\blue{Hola}}}}}$


$\mathbb{\underline{\purple{SOLUTION:}}}$


Given,

A can complete a work in 16 days

=> A will complete $\frac{1}{16}$th part of work in a day


B can complete a work in 20 days

=> B will complete $\frac{1}{20}$th part of work in a day


Let Total No. of Days taken to complete work be 'x'

As per the question,
B worked for all x days
A worked for (x - 4) days


• In a day, A complete $\frac{1}{16}$th of work

•°• A would have completed$\frac{x-4}{16}$th of work in (x-4) days

• In a day, B complete $\frac{1}{20}$th of work

•°• B would have completed$\frac{x}{20}$th of work in x days



Now,

(No. of days both worked × Work per day done by both) + (No. of days B worked alone × work per day done by B Alone) = Total work done


=> $\frac{x-14}{16} + \frac{x}{20} = 1$

=> $\frac{5(x-4) + 4x}{80} = 1$

=> $9x - 20 = 80$

=> $9x = 100$

=> $x = \frac{100}{9}$


$\mathfrak{\huge{\pink{Cheers}}}$

$\mathcal{\huge{\orange{Hope\: it\: Helps}}}$