Question

Attention Please!
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Please solve the question given in the attachment!
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Answer 1

$Hullo!!$

$Here's\:\: your\:\: answer$

$But\:\: please\:\: mark\:\: me\:\: brainliest \: \::-D$

$if\:\: Mg\:\: is\:\: present\:\: in \:\:0.4%$ $then \:\:in\:\: 100 \:\:gram\:\: of \:\:the\:\: mixture,\:\: there \:\:will\:\: be\:\: 0.4 g\:\: of \:\:Mg$

$Then\:\: in\:\: 2.5 g,\:\: there\:\: will\:\: be:$ $0.4 \:\:percent\:\: of \:\:2.5g$

$=\:\:\frac{0.4}{100} \:\:x \:\:2.5$

$= \:\:0.01 g\:\:of\:\:Mg^2^+\:\:is\:\:present\:\:in\:\:2.5g\:\:of\:\:the\:\:biomolecule$

$Then\:\:no.\:\:of\:\:Mg^2^+\:\:ions\:\:present\:\:in\:\:2.5g\:\:of \:\:the\:\:biomolecule:$

$\frac{0.01xN_a}{24}$  $\:\:=\:\:\frac{N_a}{2400}$$\:\:\:\:=\:\:option\:\:b\:\:is\:\:the\:\:right\:\:answer$