Attention!!!
Prove it :
(CosecØ-cotØ)² = (1-cosØ)/(1+cosØ)
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Taking LHS,
(CosecØ-cotØ)²
=> [(1/sinØ) - (cosØ/sinØ)]²
=> [(1-cosØ)/sinØ]²
=> (1-cosØ)²/sin²Ø
Taking RHS,
(1-cosØ)/(1+cosØ)
Rationalise it :
=> [(1-cosØ)(1-cosØ)]\[(1+cosØ)(1-cosØ)
=> (1-cosØ)²/(1-cos²Ø) [ a²-b² = (a+b)(a-b) ]
=> (1-cosØ)²/sin²Ø
LHS = RHS
Hence proved!
___________________________
★ 1 - cos²Ø = sin²Ø
★ cosecØ = 1/sinØ
★ cotØ = cosØ/sinØ
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