Question

@The tens digit of a two digit number exceeds the units digit by 5. If the digits are reversed, the new number is less by 45. If the sum of their digits is 9, find the numbers.
​

Answer 1

$hello \: mate$

Let the number be 10x+y

And the reversed number=10y+x

1)Sum of the digits is 9

➡x+y=9------(1)

2) When the digits are reversed, the new number is smaller by 45

➡10x+y-(10y+x)=45

➡10x+y-10y-x=45

➡9x-9y=45

➡x-y=5------(2)

Adding (1) and (2),

2x=14

x=7

Substituting x=7 in (2),

y=2

Thus, the number=10x+y

➡10(7)+2

➡72