Question

attitude DE and BF of parallelogram ABCD are 4 cm and 8cm long respectively one side ADis 6 cm long find the perimeter of parallelogram ABCD

Answer 1

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SOLUTION:

$area \: of \: a \: parallelogram = base \times height(correspondig \: height)$

$area \: of \: prallelogram \: abcd \: with \: ad \: as \: base \: = area \: of \: parallelogram \: abcd \: with \: ab \: as \: base$

$ad \times de = ab \times bf$

$6 \times 8 = ab \times 4$

$48 = ab \times 4$

$ab = \frac{48}{4}$

$ab = 12cm$

Since, as we know opposite sides of a parallelogram are congruent.

AD=BC=6 cm.

AB=CD=12cm.

Therefore,
we can now get the perimeter of the parallelogram ABCD ,

Perimeter of a parallelogram ABCD=AB+BC+CD+DA
=12+6+12+6
= 36cm

Hence,the perimeter of parallelogram ABCD =36cm.

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HOPE THIS HELPS YOU!!! ❤❤❤
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PROPERTIES OF PARALLELOGRAM:


1. Opposite sides are equal. 


2. Opposite angles are equal. 


3.Consecutive(Adjacent)angles are supplementary. 


4. If one angle is right then all angles are right. 


5. The diagonals of a parallelogram bisect each other. 


6. Each diagonal of a parallelogram separates it into two congruent triangles. 

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Some extra information:


A Rhombus has the properties of a parallelogram as:
Two opposite sides are equal and parallel, opposite angles are equal.
A rhombus has properties of a kite as:
Diagonals meet at a right angle, and one of the diagonal bisects (cuts equally in half) the other.

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