Atul, Bhaskar and Chetan can complete a work in 10, 20 and 25 days respectively. What is the minimum time required to finish the work if not more than two of them work together on a single day and no two consecutive days have the same pair of people working?
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Answer:
7 Days
Step-by-step explanation:
1st Day - A&B
2nd Day - A&C
and now repeat this sequence till work is completed
A's 1 day work = 1/10
B's 1 day work = 1/20
C's 1 Day work = 1/25
A+B 1 Day's work = 1/10 + 1/20 = 3/20
A+C 1 Day;s work = 1/10 + 1/25 = 7/50
2 Days work = 3/20 + 7/50 = 29/100
Work completed in 6 Days = 3 * 29/100 = 87/100
Work done on 7th day = 3/20
87/100 + 3/20 = 102/100 > 1
so on 7th Day work will finish
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