Question

atul deposite 30% of his income ina a bank after spending 50% of the remaining he had 10,500 left with him what is his income​

Answer 1

Step-by-step explanation:

Rs.30000

Step-by-step explanation:

Let the income be x

Let the income be xAtul deposit 30% of his income in a bank

Let the income be xAtul deposit 30% of his income in a bankAmount deposited in bank = \frac{30}{100}x10030x

Let the income be xAtul deposit 30% of his income in a bankAmount deposited in bank = \frac{30}{100}x10030xRemaining amount = x-\frac{30}{100}x=\frac{7x}{10}x−10030x=107x

Let the income be xAtul deposit 30% of his income in a bankAmount deposited in bank = \frac{30}{100}x10030xRemaining amount = x-\frac{30}{100}x=\frac{7x}{10}x−10030x=107xNow he spend 50%

Let the income be xAtul deposit 30% of his income in a bankAmount deposited in bank = \frac{30}{100}x10030xRemaining amount = x-\frac{30}{100}x=\frac{7x}{10}x−10030x=107xNow he spend 50%So, Remaining = \frac{7x}{10}-\frac{50}{100} \times \frac{7x}{10}107x−10050×107x

Let the income be xAtul deposit 30% of his income in a bankAmount deposited in bank = \frac{30}{100}x10030xRemaining amount = x-\frac{30}{100}x=\frac{7x}{10}x−10030x=107xNow he spend 50%So, Remaining = \frac{7x}{10}-\frac{50}{100} \times \frac{7x}{10}107x−10050×107xWe are given that he had 10,500 left with him

Let the income be xAtul deposit 30% of his income in a bankAmount deposited in bank = \frac{30}{100}x10030xRemaining amount = x-\frac{30}{100}x=\frac{7x}{10}x−10030x=107xNow he spend 50%So, Remaining = \frac{7x}{10}-\frac{50}{100} \times \frac{7x}{10}107x−10050×107xWe are given that he had 10,500 left with himSo,  \frac{7x}{10}-\frac{50}{100} \times \frac{7x}{10}=10500107x−10050×107x=10500

Let the income be xAtul deposit 30% of his income in a bankAmount deposited in bank = \frac{30}{100}x10030xRemaining amount = x-\frac{30}{100}x=\frac{7x}{10}x−10030x=107xNow he spend 50%So, Remaining = \frac{7x}{10}-\frac{50}{100} \times \frac{7x}{10}107x−10050×107xWe are given that he had 10,500 left with himSo,  \frac{7x}{10}-\frac{50}{100} \times \frac{7x}{10}=10500107x−10050×107x=10500x=30000x=30000

Let the income be xAtul deposit 30% of his income in a bankAmount deposited in bank = \frac{30}{100}x10030xRemaining amount = x-\frac{30}{100}x=\frac{7x}{10}x−10030x=107xNow he spend 50%So, Remaining = \frac{7x}{10}-\frac{50}{100} \times \frac{7x}{10}107x−10050×107xWe are given that he had 10,500 left with himSo,  \frac{7x}{10}-\frac{50}{100} \times \frac{7x}{10}=10500107x−10050×107x=10500x=30000x=30000Hence his income is Rs.30000

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Answer 2

Answer:

Let’s say Atul monthly income is 100 Rs.

Atul spends 30 Rs. on food, remaining Rs. = 100 - 30 = 70 Rs.

Spending on conveyance and clothes = 40% of 70 = (40/100) x 70 = 28 Rs.

Remaining Rs. = 70 - 28 = 42 Rs.

Saving = 50% of 42 = (50/100) x 42 = 21 Rs.

Applying unitary method now,

If monthly income is 100 Rs. then saving is 21 Rs.

If monthly income is 1 Rs. then saving = (21/100) Rs.

If monthly income is 18400 then saving = (21/100) x 18400

Therefore, Atul monthly saving = 21 x 184 = 3864 Rs.