Atul deposited 30% of his income in a bank. After spending 50% of the remaining he had rupees 10500 left with him. What is his income
Answers
Answer:
₹30, 000
Step-by-step explanation:
let his income be X
deposited money=30%of X
=3X/10
X-3X/10=7X/10
spent money=50/100 × 7X/10
=7X/20
7X/20=10500
X=10500×20/7
X=1500×20
X=₹30,000
Let, his total income be, 'x'
So, he deposited to the bank = (x*30/100)
= 3x/10
∴ The amount of money left after depositing in the bank = (x - 3x/10)
= (10x - 3x)/10
= 7x/10
So, after depositing for the bank he spent = (7x/10)*(50/100)
= (7x*50/10*100)
= (7x/10*20)
= 7x/20
∴ Finally the amount of money left =(7x/10) - (7x/20)
=(14x-7x)/20 [∵ L.C.M. of 10 and 20 is 20]
= 7x/20
According to the given condition,
7x/20 = 10500
⇒ 7x = 10500*20
⇒ x = 10500*20/7
⇒ x = 1500*20
⇒ x = ₹ 30000
So, Atul's income is ₹ 30000
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