atul has to score a minimum of 40.5%marks for passing an examination he gets 400marks and faileds by 86 marks find tha maximum marks solve this question is
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let the passing marks be x
400 + 86 =x
x = 486
let maximum marks be y
passing marks = 40.5% of y
486 = 40.5 % of y
y = (486 * 100)/40.5
y = 1200
Therefore,maximum marks = 1200
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