Atul sold two mobiles for Rs.9900 each. At one mobile, he gained 10% and on other, he lost 10%. Find his gain or loss in a transaction?
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Answered by
15
(10/10)^2 =1% loss
1/100×2×9900=198rs loss
1/100×2×9900=198rs loss
Answered by
23
selling price of two mobile =9900
one phone got 10%profit so selling price=110/100 of X =11x/10
others lost 10%percent so selling price=90/100of X=9x/10
according to question,
11x/10+9x/10=9900
20x/10=9900
2x=9900
X=9900÷2
X=4950
selling price of one phone =11×4950/10
=11×495
selling price of other=9×4950/10
=9×495
u please find the sum of this two and then if 9900 is greater means loss and smaller means profit
one phone got 10%profit so selling price=110/100 of X =11x/10
others lost 10%percent so selling price=90/100of X=9x/10
according to question,
11x/10+9x/10=9900
20x/10=9900
2x=9900
X=9900÷2
X=4950
selling price of one phone =11×4950/10
=11×495
selling price of other=9×4950/10
=9×495
u please find the sum of this two and then if 9900 is greater means loss and smaller means profit
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