Atul starts from his house at 6.45am and cycles down to reach his school at 7.15 am . The distance of the house from school is 6km . Find the speed
Answers
Answer:
Hello Friend !
The answer to your query is given below. Please refer it !
As given in the question, the student walks from his house at 6:30 a.m. and reaches his school at 7:15 a.m. .
Therefore, the total time taken to reach the school is :
7:15 - 6 : 30 = 45 min. = 45 × 60 = 2700 sec [ ∵ 1 min = 60 sec ]
Also, total distance between the school and the home = 6 km = 6 × 1000 = 6000 m [ ∵ 1 km = 1000 m ]
Now, speed = distance / time
⇒ speed = \frac{6000}{2700}
2700
6000
⇒ speed = 2.22 m/s ≈ 2 m/s
Or 45 min = \frac{45}{60}
60
45
hr
⇒ speed = \frac{6 km * 60}{45 hr}
45hr
6km∗60
= 8 km/hr
Step-by-step explanation:
please mark me
Step-by-step explanation:
I will give you the answer.
distance
speed= ______
time
So,speed=6km/30min
= 6000m/30min
=20km/min
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