Question

AU298 = -10.5 KJ and ASI = -44.1 JK
Calculate AH298 for the reaction and predict whether the reaction is spontaneous of
15, The equilibrium constant at 298 K for the reaction in a state of equilibrium is:
Cu (S) + 2 Ag+ (aq)
=Cu²+ (aq) + 2Ag (S) is 2.0 X 10'5.
In a solution in which copper has displaced some silver ions from solution the concentration of Cu?
ions is 1.8 X 10^2 mol-' and the concentration of Ag+ ions is 3.0 X 10-moll. Is this system at
equilibrium?​

Answer 1

Answer:

The figure is shown in image

The figure is shown in image Now apply Pythagoras theorem in ΔOAB

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA 2

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA 2 =AB

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA 2 =AB 2

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA 2 =AB 2 +OB

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA 2 =AB 2 +OB 2

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA 2 =AB 2 +OB 2

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA 2 =AB 2 +OB 2 5

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA 2 =AB 2 +OB 2 5 2

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA 2 =AB 2 +OB 2 5 2 =OB

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA 2 =AB 2 +OB 2 5 2 =OB 2

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA 2 =AB 2 +OB 2 5 2 =OB 2 +3

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA 2 =AB 2 +OB 2 5 2 =OB 2 +3 2

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA 2 =AB 2 +OB 2 5 2 =OB 2 +3 2

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA 2 =AB 2 +OB 2 5 2 =OB 2 +3 2 OB=4c.m.

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA 2 =AB 2 +OB 2 5 2 =OB 2 +3 2 OB=4c.m. similarly for ΔABD

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA 2 =AB 2 +OB 2 5 2 =OB 2 +3 2 OB=4c.m. similarly for ΔABDBD=4c.m.

The figure is shown in image Now apply Pythagoras theorem in ΔOAB OA 2 =AB 2 +OB 2 5 2 =OB 2 +3 2 OB=4c.m. similarly for ΔABDBD=4c.m.Hence Distance b\w center of the circles is 8 c.m.