Science, asked by georgeunpa, 9 months ago

Au2O3 decomposes on heating;​

Answers

Answered by lalankumar99395
4

Explanation:

The thermal decomposition of oxide gold(III) to produce gold and oxygen. This reaction takes place at a temperature of 160-290°C.

PLEASE MARK BRAINLIEST ANSWER AND FOLLOW ME

Answered by ishwaryam062001
0

Answer:

2 Au2O3 → 4 Au + 3 O2

Explanation:

Au2O3 is an ionic compound composed of gold (Au) and oxygen (O) ions. When heated, the robust electrostatic forces that preserve the ions collectively are broken, permitting the ions to separate and shape their elemental forms.

The gold ions shape gold atoms and the oxygen ions shape oxygen gas. This system is an instance of a thermal decomposition reaction.

Au2O3 is an ionic compound composed of gold (Au) and oxygen (O) ions. When heated, these ions destroy aside and shape their elemental forms. This technique is acknowledged as thermal decomposition and is represented by means of the following balanced equation: two Au2O3 → four Au + three O2.

This equation indicates that two molecules of Au2O3 will decompose into 4 atoms of gold and three molecules of oxygen gas. The robust electrostatic forces between the ions are damaged due to the heat, permitting the atoms to separate and shape their elemental forms. This technique is an instance of a thermal decomposition response and is used in a range of industrial applications, such as the manufacturing of gold nanoparticles.

For more such related questions : https://brainly.in/question/32667309

#SPJ2

Similar questions