Math, asked by notme99, 5 hours ago

(AUB)'= A'nB' (A×B) U(A×C) (A∆B = (AUB) - (AnB)

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Answered by shardakuknaa

1

Answer:

your answer is in the attachment

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Answered by Anonymous

2

Answer:

... (A'NB) vii) (AUB) = (A-B) U (ANB) (B-A) viii) An (BAC) = (ANB) A (ANC) ix) n(AUB) = n(A) + n(B) - n(ANB) 2x n(B)=(A'NB) + n( AB) ...

answer is In attachment ☺️❤️

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