Audi A body moving on the ground with a velocity of 15 metre per second comes to rest after covering a distance of 25 the acceleration due to gravity is 10 metre per second square find the coefficient of friction between the ground and the body
Answers
Answered by
6
Answer:
0.45
Explanation:
Stopping distance is calculated by
- S = u²/(2μg)
Where
- S = Stopping distance
- u = Initial velocity
- μ = Coefficient of friction
- g = Acceleration due to gravity
From above,
μ = u²/(2Sg)
= (15 m/s)² / (2 × 25 m × 10 m/s²)
= (225) / (500)
= 0.45
Similar questions