aunty has the twice as many Marbles as Pandey and send it has half as many as anti and Pandey put together if it is a 75 Marbles more than Sandy how many does each of them have
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Let Pandy has x no. of marbles.
Thus, no. if marbles with Andy= 2x
No. of marbles with Sandy=( x+2x)/2 = 3x/2
A/q,
2x= 75+3x/2
=> 2x= (150+3x)/2
=> 4x = 150+3x
=> x= 150.
Thus, Pandy has 150 marbles.
Marbles with Andy= 2*150= 300
Marbles with Sandy= (3*150)/2
= 450/2=> 225.
Hope This Helps :)
Thus, no. if marbles with Andy= 2x
No. of marbles with Sandy=( x+2x)/2 = 3x/2
A/q,
2x= 75+3x/2
=> 2x= (150+3x)/2
=> 4x = 150+3x
=> x= 150.
Thus, Pandy has 150 marbles.
Marbles with Andy= 2*150= 300
Marbles with Sandy= (3*150)/2
= 450/2=> 225.
Hope This Helps :)
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